To find words but only with requested number of specific letters

Question

I'm working on a script that supposed to find words that contain given letters by user has input. The script works however not exactly in a way I want. For example if I input letters:stop The scripts prints out words I have input but are repeated such like: stop, stoper, stereotype. There shouldn't be the word: "Stereotype" because I've input only only one: "e" and "t

letters = input('letters: ')
words = open('newwords').read().splitlines()

#print (words)
print(".......................")

for word in words:

     if all(x in word for x in letters):
        for x in letters:
            if word.count(x) == letters.count(x):
                print(word)

Answer 1

I don't know how your 'newwords' look like. I try something like this:

test.txt:

stop
stoper
stereotype

the code is same as yours except words = open('test.txt').read().splitlines()

Output:

letters: stop
.......................
stop
stop
stop
stop
stoper
stoper
stoper
stoper
stereotype
stereotype
stereotype

Your for x in letters check one letter at a time. As there is same count for "s", "o" and "p", stereotype is printed three times (not four because of different count for "t") .

Suggestion:

You may change your last part to this so the word only printed out after all letter count is checked.

for word in words:
    if all(word.count(x) == letters.count(x) for x in letters):
        print(word)