Finding the number of upper and lower case letter in a string in python

Question

when I run the code it always shows 0 as results.... CODE:

def case_counter(string):
    lower=0
    upper=0
    for char in string:  
        if (string.islower()):
            lower=lower+1
        
        elif (string.isupper()):
            upper=upper+1
        
    print('the no of lower case:',lower)
    print('the no of upper case',upper)
string='ASDDFasfds'        
case_counter(string)

RESULT: the no of lower case: 0 the no of upper case 0 EXPECTED: the no of lower case:5 the no of upper case 5

Answer 1

我认为你需要使用char.islower()而不是string.islower()并且你可以做lower+=1而不是lower=lower+1和upper

Answer 2

Your conditionals are incorrect. Update string.islower() and string.isupper() to char.islower() and char.isupper()

Answer 3

You need to iritate over each character indiviudaly. Now your program checks if whole string is written in uppercase or lowercase.

This means your code should look something like this:

def upper_lower(text):
    upper = 0
    lower = 0
    for i in text:
        if i.isupper():
            upper += 1
        else:
            lower +=1
    print('the no of lower case:',lower)
    print('the no of upper case',upper)

Answer 4

When comparing lower and higher value for your purpose you have to use "char" variable Like the example in this code

def case_counter(string):
    lower=0
    upper=0
    for char in string:  
        if (char.islower()):
            lower=lower+1
        
        elif (char.isupper()):
            upper=upper+1
        
    print('the no of lower case:',lower)
    print('the no of upper case',upper)
string='ASDDFasfds'        
case_counter(string)