Reading a string into an 2D array of strings in C

Question

Suppose I have a 2D array of string in the form ar[i][j], where i refers to the ith string in the array and j is the specific index of a character in that string. I wish to make a function that gets the size from the user (number of names), and let them input names separated by a whitespace. Here's my attempt at the function:

void readNames(char nameptr[][80], int *size)
{
   int i;
   char dummychar;

   printf("Enter size:\n");
   scanf("%d", size);
   scanf("%c", &dummychar);
   printf("Enter %d names:\n", *size);
   for ( i = 0; i < size; i++)
   {
       scanf("%s", &nameptr[i]);
   }
   printf("Test?");

}

Here's a sample input:

Enter size:
5
Enter 5 names:
Sam Paul John Mary Nick

After this, the array that was passed into the function, nameptr, should have the following values:

nameptr[0] = "Sam\0"
nameptr[1] = "Paul\0"
nameptr[2] = "John\0"
nameptr[3] = "Mary\0"
nameptr[4] = "Nick\0"

However, something seems to be wrong at the last scanf step, as the program simply times out and doesn't print the last test statement. I'm not sure if it's a syntax error, and I'm not sure how to scanf properly into an 2D array of strings in this case. Any help and insights are appreciated, thank you very much.

Answer 1

It turns out the mistake is in the line:

   for ( i = 0; i < size; i++)

I have passed the size into the function via a pointer, so it should be

for ( i = 0; i < *size; i++)

and the function works as expected. Thanks for reading.