Counting words in a apropos command

Question

I have this command apropos -l apple . I want to count the word "apple" from the output of the command. I am a beginner in UNIX commands, and have an idea that I have to use grep or wc , but I'm not sure how. Any help would be appreciated.

Answer 1

apropos -l apple | grep -io apple

There are many options within grep that can help you meet your objective and the above is just an example.

Take the output of apropos -l and then pipe through to grep. With grep, we search for all "apple" entries with -i to show any case combinations. We then finally output the generated list through to wc -l to count the lines and therefore the entries,