How to replace last 3 character with x from string in php?

Question

$string = "Hello world country";  
echo substr($string, 0, -3).'xxx';

Actual output:

Hello world counxxx

Expected output:

Hexxx woxxx counxxx

How can I do this?

Answer 1

You need to use explode() , foreach() , implode() and substr()

$string = "Hello world india";

$array = explode(' ',$string);

foreach($array as &$ar){
    
    $ar = substr($ar, 0, -3).'xxx';
}
echo implode(' ',$array);

Output: https://3v4l.org/RhCA7

Note: My assumption here is words are separated with space and each word have letter count >= 3

Answer 2

Answer provided by @Alive to Die is great.

Another way is to use str_word_count() and array_map() :

$string = "Hello world country";
$words = str_word_count($string, 1);
$words = array_map(function($word) {
     if (strlen($word) < 3) return $word;
     return substr($word, 0, -3) . 'xxx'; 
}, $words);
echo implode(' ', $words);

Output:

Hexxx woxxx counxxx

To mask the half of each words, you could use:

$string = "Hello world country";
$words = str_word_count($string, 1);
$words = array_map(function($word) {
     $half = floor(strlen($word)/2);
     return substr($word, 0, -$half) . str_repeat('x', $half); 
}, $words);
echo implode(' ', $words);

output:

Helxx worxx counxxx

Answer 3

You can use explode and substr :

$string = "Hello world country"; 
$array = explode(' ',$string);
foreach($array as $ar){
    $ar = substr($ar,0,-3).'xxx';
    echo $ar." ";
}

Expected Output: Hexxx woxxx counxxx