how to replace square brackets from a string in groovy?

Question

I have a string from which I get just the number with 6 charactes using findAll() but tha returns me the number in this format [111111] I want to get rid of the square brackets and save it to a variable. I have tried this but it does not remove the brackers:

def msg = "Fix for bug 861768 and 3v3 player number 24"
def bugNumber = msg.findAll( /\d{6}/ ).toString()
bugNumber.replaceAll("\\[", "").replaceAll("\\]","");
println bugNumber

This is the output I get: [861768]

No need to say I just started with groovy so probably the code has some mistakes. But any help is appreciated

Answer 1

msg.findAll( /\d{6}/ ) returns an array of strings found.

if you want just first element found then use msg.findAll( /\d{6}/ ) [0]

or msg.find( /\d{6}/ )

if you want all of them delimited with coma msg.findAll( /\d{6}/ ).join(',')