Find first occurrence of a character before a keyword with Regex

Question

I'm trying to extract each first occurrence of a character before a keyword. In the string below, the idea would be to extract the position of ">" just for lines that contain the word "Change", and should match 3 ">" on the 3 last lines.

<th class="col_heading level0 col5" >Thing</th>
<th class="col_heading level0 col6" >Second Thing</th>
<th class="col_heading level0 col7" >Third Thing</th>

<th class="col_heading level0 col5" >Thing Change</th>
<th class="col_heading level0 col6" >Second Thing Change</th>
<th class="col_heading level0 col7" >Third Thing Change</th>

I have a begin of answer, using look-alike operator, I'm currently able to extract text from the ">" to the "Change" Keyword, but I'm stuck to extract just the ">" properly

([^"]*(?=Change))

Answer 1

Use

>(?=.*?Change)

See regex proof .

EXPLANATION

--------------------------------------------------------------------------------
  >                        '>'
--------------------------------------------------------------------------------
  (?=                      look ahead to see if there is:
--------------------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
--------------------------------------------------------------------------------
    Change                   'Change'
--------------------------------------------------------------------------------
  )                        end of look-ahead