eg:
JSONObject jsonObj = new JSONOject();
jsonObj.put("stringified_array", "[1,2]");
So, when I debugged it, the jsonObj properties were
key : "stringified_array", value : [1,2] (JSONArray)
Edit: Here is the link for sample code: https://onlinegdb.com/UbV6VXvpJ . Code won't compile due to missing packages in online ide, just for better understanding of scenario I have added the link.
Here is why, if you look at the declaraction of constructor of JSONObject , you will find what you are looking for. One of the constructor of JSONObject class looks like following:
public org.json.JSONObject put(java.lang.String key, java.util.Map<?,?> value) throws org.json.JSONException { /* compiled code */ }
If you know how to do reverse engineering , you should be able to find more about the actual implementation:)!
Hopefully, this will help you out!
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