How can I convert a date present in format 2017-06-30 23:59:59.000
to JUNE 2017
?
I need to do this using SQL Query.
You can use the FORMAT
function for this
SELECT FORMAT(CAST('2017-06-30 23:59:59.000' AS datetime), 'MMMM yyyy');
Result
June 2017
The DATENAME
function will return the Name of the month
SELECT DATENAME(month,'2017-06-30 23:59:59.000')+' '+CAST(YEAR('2017-06-30 23:59:59.000') AS VARCHAR) 'Month Name'
SELECT DATENAME(mm,'2017-06-30 23:59:59.000')+' '+CAST(YEAR('2017-06-30 23:59:59.000') AS VARCHAR) 'Month Name'
SELECT DATENAME(m,'2017-06-30 23:59:59.000')+' '+CAST(YEAR('2017-06-30 23:59:59.000') AS VARCHAR) 'Month Name'
This will return
June 2017
If you want to get it from a table, then replace the table and column name in the below query.
SELECT DATENAME(month,ColumnName)+' '+CAST(YEAR(ColumnName) AS VARCHAR) 'Month Name'
FROM TabeName
The DATENAME function in sql server returns the name of the month.
SELECT DATENAME(MM, GETDATE()) + ' ' + CAST(YEAR(GETDATE()) AS VARCHAR()) AS
[Month YYYY]
For more information you can refer: http://www.sql-server-helper.com/tips/date-formats.aspx
Here is the best answer for MS SQL.
Create table Test(
SampleDate datetime
)
insert into Test(SampleDate)values('07/20/2021 10:20:05'),('08/21/2021 20:30:11')
Here is your query to get the format
select FORMAT(SampleDate, 'MMMM yyyy') YourFormat from Test
--select FORMAT(SampleDate, 'MM/dd/yyyy hh:mm tt') EditedDate from Test
Above query return the following output:
July 2021
August 2021
SELECT DATE_FORMAT(column_name, "%M %Y") as alias_column_name FROM tabel_name
Example
SELECT DATE_FORMAT(created_at, "%M %Y") as created_at FROM tabel1
use sql's DATE_FORMAT(date, format) function.
https://www.w3schools.com/mysql/func_mysql_date_format.asp <- visit this website.
https://www.mssqltips.com/sqlservertip/1145/date-and-time-conversions-using-sql-server/ <- Date and Time Conversions Using SQL Server
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