Split a string column to new columns postgresql

Question

I have a column which can contain over 20 different values and they are seprated by semicolon. for example: A;B;C;D;E;F;G;H;.... , I need to split all the values in new columns. I tried to split it with SPLIT_PART() , but it seems i need to sepcify which position do i want from the string. But in my case, there are too many values and it's not very effcient to do like this.

I wonder if there's anyway that I can split them by; and all value will be saved in a new column?

Answer 1

Split the string into an array and select array elements. A CTE stands for the table.
Here is an illustration for 10 columns. Still somewhat verbose but of a regular nature.

with the_table(s) as 
(
 values
 ('A01;B01;C01;D01;E01;F01;G01;H01;I01;J01'),
 ('A02;B02;C02;D02;E02;F02;G02;H02;I02;J02'),
 ('A03;B03;C03;D03;E03;F03;G03;H03;I03;J03')
),
arr(a) as 
(
 select string_to_array(s,';') from the_table
)
select 
  a[1] c1,a[2] c2,a[3] c3,a[4] c4,a[5]  c5,
  a[6] c6,a[7] c7,a[8] c8,a[9] c9,a[10] c10 -- ...
from arr;

c1	c2	c3	c4	c5	c6	c7	c8	c9	c10
A01	B01	C01	D01	E01	F01	G01	H01	I01	J01
A02	B02	C02	D02	E02	F02	G02	H02	I02	J02
A03	B03	C03	D03	E03	F03	G03	H03	I03	J03