Python create path with file

Question

Is there a way to create a file and automatically create its path?

for example:

with open("./path/to/file/data.txt", "w") as f:
    f.write("hello")

I want it to create the path ./path/to/file and then create the file data.txt and open it. instead it will give the error

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
FileNotFoundError: [Errno 2] No such file or directory: './path/to/file/data.txt'

I don't want to have to manually create the path one folder at a time.

Answer 1

import os

os.makedirs(os.path.dirname(fullPath))

Answer 2

To know or get a file location or path, you first of all create a file module, on creating the file name module, python already knows its path. To create a module name use

               import os
             
               os.mkdir('data.txt')

You can use the code below to know or display the file module path displayed in your output shell.

               import os

               result = os.getcwd()

You can then further to create the file using

               with open('data2.txt', 'w') as f:
               f.write('You are good')

I added 2 to the file name ie 'data2.txt' because python does not permit same name for file module as file name in the same directory.