ID | NAME | DATE | STATUS |
---|---|---|---|
1 | Joe | 01-22 | Approved |
1 | Joe | 01-22 | Pending |
2 | Bill | 02-22 | Approved |
2 | Bill | 02-22 | Sent back |
3 | John | 01-22 | Approved |
4 | Bob | 02-22 | Pending |
How do I only return one row per ID, placing priority on approved?
Example: for Id 1 I only want the row that is approved and not the one that is pending.
Some Id's may only have 1 record for example ID 4 has just one record and is pending.
What I want is: IF status = approved and pending for the same Id then keep the approved record and not select the pending record
If status = pending then keep that record
This will preferentially select Approved, then Pending, then everything else. If you don't want "everything else" just filter in the WHERE clause.
select id,
name,
date,
status
from (
select *,
row_number() over
( partition by id
order by case when status = 'Approved' then 1
when status = 'Pending' then 2
else 3
end asc,
date
) as first_by_date_with_approved_precedence
from your_table
) tmp
where first_by_date_with_approved_precedence = 1
It could also be as easy as the following (provided status is not blank or null)
Select Top 1 with ties *
from YourTable
order by row_number() over (partition by id order by Status)
Results
ID NAME DATE STATUS
1 Joe 01-22 Approved
2 Bill 02-22 Approved
3 John 01-22 Approved
4 Bob 02-22 Pending
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