How to extract a single character from the elements in vector<char*>?

Question

I am trying to extract a single element from a string literal included a list composed of string literals. I used VS Code.

First, I used pointer to make the array of string literals and succeeded in the extracting particular single character in C.

I ran following code to check this:

#include <stdio.h>

int main()
{ 
  char* list[]={"abc","def","ghi"};
  printf("%c\n",list[1][1]);
  return 0;
}

Then, I tried to use vector instead of array to make the list consists of string literals in C++.
I ran following code but failed:

#include <bits/stdc++.h>
using namespace std;

int main()
{
  vector<const char*> list;
  list = {"abc", "def", "ghi"};
  for (int i = 0; i < 3; i++){
    const char* temp = list[i];
    cout<<temp[3]<<endl;
  }
  return 0;
}

When I ran the code above, just blank was displayed:

I also tried changing const char* to char* , but it didn't worked well, too.

#include <bits/stdc++.h>
using namespace std;

int main()
{
  vector<char*> list;
  list = {"abc", "def", "ghi"};
  for (int i = 0; i < 3; i++){
    char* temp = list[i];
    cout<<temp[3]<<endl;
  }
  return 0;
}

I am not sure why my codes does not work well to extract the single character included the element of list . Could you please tell me the reason why my didn't work well?
I appreciate if you could help me.

Notations
Based on the comments, I revised my code. I changed char* to string as following:

#include <bits/stdc++.h>
using namespace std;

int main()
{
  vector<string> list;
  list = {"abc", "def", "ghi"};
  for (int i = 0; i < 3; i++){
    string temp = list[i];
    cout<<temp[3]<<endl;
  }
  return 0;
}

However, the output is also blank as well.

Answer 1

temp[3] is null character. the literal "abc" means the array {'a', 'b', 'c', '\0'} .

Change

cout<<temp[3]<<endl;

To

cout<<temp[2]<<endl;

Answer 2

you are using temp[3] but "abc" means an array of size 4 as follows:

{'a', 'b', 'c', '\0'}

Where '\0' represents the termination of the string. So temp[3] is same as '\0' .

Please use temp[2] instead to access the last character of the string.