how can i convert the avg values to int, and how can I round up the hours to the days (change 72 days 32:01:52.694268 to just be 73)

Question

select day_of_week, avg(booking_time)
from(SELECT check_in_date - booked_at as booking_time, EXTRACT (dow FROM 
    check_in_date)day_of_week
    FROM bookings 
    ) as table1
where EXTRACT(epoch FROM booking_time)/3600 > 0
group by day_of_week
order by avg(booking_time) desc;

here's the output table:

day_of_week	avg
4.0	72 days 32:01:52.694268
5.0	57 days 34:00:09.228322
3.0	50 days 26:30:19.840091
6.0	41 days 33:12:01.010234
0.0	36 days 14:35:36.59173
2.0	34 days 28:15:35.384787
1.0	31 days 10:52:57.718717

Answer 1

The quick answer:

select  extract(days from justify_hours('72 days 32:01:52.694268'::interval));
73

Further explanation. Use justify_hours fromDateTime functions to convert the hours portion of the interval to a day if appropriate.

select  justify_hours('72 days 32:01:52.694268'::interval);
      justify_hours      
-------------------------
 73 days 08:01:52.694268

Then use extract from the same link above to pull the days portion of the interval out:

select  extract(days from justify_hours('72 days 32:01:52.694268'::interval));
 extract 
---------
      73