Regular Expression: 0-9 A-Z a-z or any of these '!#$%&'*+-/=?^_`{|}~

Question

I need to regex string myString to only have:

• 0-9
• AZ or az
• any of these characters '!#$%&'*+-/=?^_`{|}~.

This is my code line:

new Regex("[a-zA-Z0-9]").IsMatch(myString);

So far I have [a-zA-Z0-9] and this works fine for the first two listitems. Currently tearing my hair out (and it's so nice I want to keep it) over metacharacters and getting nowhere.

Any help would be greatly appreciated. Thanks. Dave

Answer 1

嗨那里如果您只想要字符串中列出的字符，那么它非常简单。但您需要匹配开头的行尾

new Regex("^[a-zA-Z0-9'!#$%&'*+/=?^_`{|}~.-]*$").IsMatch(myString);

Answer 2

"[a-zA-Z0-9'!#$%&'*+/=?^_`{|}~.-]"

检查（“ - ”）减号是[]序列中的最后一个字符

Answer 3

Meta characters are fine between brackets, as long as you escape the significant ones. Moreover the dash MUST be the last one of your sequence.

new Regex("[a-zA-Z0-9'!#$%&'*+/=?^_`{|}~-]").IsMatch(myString);

Answer 4

尝试：

var re = "[a-zA-Z0-9" +  Regex.Escape("'!#$%&'*+-/=?^_`{|}~.") + "]";