Regex Pattern to Extract Email Data

Question

I'm retrieving raw text (includes header, and message) from a POP server. I need to capture everything after the header which is terminated by a blank line between it and the user message.

At the same time I'm wanting to ignore anything from original messages if it's a reply. The start of a reply for the emails I'm parsing start with

------Original Message------

An example email might look like this

Return-Path: ...
...
More Email Metadata: ...

Hello from regex land, I'm glad to hear from you.
------Original Message------
Metadata: ...
...

Hey regex dude, can you help me? Thanks!

Sincerely, Me.

I need to extract "Hello from regex land, I'm glad to hear from you." and any other text/lines prior to the original message.

I'm using this regex right now (C# in multiline mode)and it seems to work except it's capturing ------Original Message------ if the body is blank. I'd rather just have a blank string instead.

^\s*$\n(.*)(\n------Original Message------)?

Edit
I haven't down voted anyone and if you happen to downvote, it's usually helpful to include comments.

Answer 1

Why don't you not use DotnetOpenMail ? Using a regex to do this is a wrong approach, you'd be better off using a dedicated email handler instead....

Answer 2

The reason for this is that you have an extra \\n inside the parenthesis. If the body is blank, there is no extra newline there. Therefore, try this:

^\s*$\r\n(.*)(^------Original Message------$)?

If you don't want the newline at the end of the body, you can still use string.Trim() on the matched part.

Note: This assumes that the input uses \\r\\n line terminators (which is required in e-mail headers according to the MIME standard).

Answer 3

您需要替换(\\n------Original Message------)与(?=(\\n------Original Message------))前瞻不返回部分，只是为了确保它在那里