简体   繁体   中英

How do I convert an Array to a List<object> in C#?

如何在C#中将Array转换为List<object>

List<object> list = myArray.Cast<Object>().ToList();

如果数组元素的类型是引用类型,则可以.Cast<object>()因为C#4添加了接口协方差,即IEnumerable<SomeClass>可以被视为IEnumerable<object>

List<object> list = myArray.ToList<object>();

使用构造函数: new List<object>(myArray)

List<object>.AddRange(object[]) should do the trick. It will avoid all sorts of useless memory allocation. You could also use Linq, somewhat like this: object[].Cast<object>().ToList()

The List<> constructor can accept anything which implements IEnumerable, therefore...

        object[] testArray = new object[] { "blah", "blah2" };
        List<object> testList = new List<object>(testArray);
private List<object> ConvertArrayToList(object[] array)
{
  List<object> list = new List<object>();

  foreach(object obj in array)
    list.add(obj);

  return list;
}

如果数组项和列表项相同

List<object> list=myArray.ToList();

Everything everyone is saying is correct so,

int[] aArray = {1,2,3};
List<int> list = aArray.OfType<int> ().ToList();

would turn aArray into a list, list. However the biggest thing that is missing from a lot of comments is that you need to have these 2 using statements at the top of your class

using System.Collections.Generic;
using System.Linq;

I hope this helps!

您还可以直接使用数组初始化列表:

List<int> mylist= new List<int>(new int[]{6, 1, -5, 4, -2, -3, 9});

其他方式

List<YourClass> list = (arrayList.ToArray() as YourClass[]).ToList();

这允许您发送一个对象:

private List<object> ConvertArrayToList(dynamic array)

Here is my version:

  List<object> list = new List<object>(new object[]{ "test", 0, "hello", 1, "world" });

  foreach(var x in list)
  {
      Console.WriteLine("x: {0}", x);
  }

You can try this,

using System.Linq;
string[] arrString = { "A", "B", "C"};
List<string> listofString = arrString.OfType<string>().ToList();

Hope, this code helps you.

The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM