Python. Print mac address out of 6 byte string

Question

I have mac address in 6 byte string. How would you print it in "human" readable format?

Thanks

Answer 1

import struct
"%x:%x:%x:%x:%x:%x" % struct.unpack("BBBBBB",your_variable_with_mac)

Answer 2

There's no need to use struct :

def prettify(mac_string):
    return ':'.join('%02x' % ord(b) for b in mac_string)

Although if mac_string is a bytearray (or bytes in Python 3), which is a more natural choice than a string given the nature of the data, then you also won't need the ord function.

Example usage:

>>> prettify(b'5e\x21\x00r3')
'35:65:21:00:72:33'

Answer 3

在Python 3.8及更高版本中，您可以只使用bytes.hex 。

b'\x85n:\xfaGk'.hex(":") // -> '85:6e:3a:fa:47:6b'

Answer 4

Try,

for b in addr:
    print("%02x:" % (b))

Where addr is your byte array.

Answer 5

s=b'\\x04NZ\\xdf\\x7f\\xab'

1) import struct ssid_2 = "%02x:%02x:%02x:%02x:%02x:%02x" % struct.unpack("BBBBBB", s)

or

2) ':'.join(f'{x:02x}' for x in s)

but 1) is way faster than 2)

Answer 6

Is the usual hex format not human-readable enough? ( see this for a way to convert a byte to hex)

de:ad:be:ef:ca:fe

Incidentally, this is the way MAC addresses are displayed in most software (just Windows uses dashes instead of colons).