SQL: retrieve unique structure

Question

I'm having trouble finding exclusive group data set for the given query paramter.

My table is like this:

GROUP_ID  DOMAIN_ID (unique)
--------  ---------
111       2123
111       2124
111       2125
111       2126
112       2124
112       2125
113       2124
113       2125
113       2126
114       2124
114       2127
114       2128

Ok, now I need to find a GROUP_ID where DOMAIN_ID contains and ie it should not return 111 or 113 from the example above. 包含和即它不应该从上面的示例返回111或113。

Limitation: Can't use SP/Function. It should be one SQL query.

Thanks very much for your time in advance.

Answer 1

如果按groupid分组，则可以使用HAVING子句查找min（domainid）= 2124和max（domainid）= 2125的组

Answer 2

Here is one way to do it:

SELECT group_id FROM table WHERE group_id IN (SELECT group_id FROM table WHERE domain_id in (2124, 2124)) GROUP BY group_id HAVING count(group_id) = 2;

The benefit with this approach is that the two domain_ids don't need to be sequential as in one of the other answers.

Using your data in sqlite3, this produces:

sqlite> create table t (a int, b int);
sqlite> .import data t
sqlite> SELECT a FROM t WHERE a IN (SELECT a FROM t WHERE b in (2124, 2124)) GROUP BY a HAVING count(a) = 2;
a
112

Answer 3

Are you trying to get something like this?

SELECT DOMAIN_ID, COUNT(*) AS OCCURRENCES FROM TEST WHERE DOMAIN_ID = '2124' OR DOMAIN_ID =     '2125' GROUP BY DOMAIN_ID

results in:

DOMAIN_ID   OCCURRENCES     2124        4
2125        3

Answer 4

If you don't have (group_id,domain_id) duplicates you can use

SELECT group_id, 
  SUM(CASE WHEN domain_id=2124 OR domain_id=2125 THEN 1 ELSE -1 END) AS matches 
FROM `mytable`
GROUP BY group_id
HAVING matches=2

Answer 5

SELECT GROUP_ID
FROM atable
GROUP BY GROUP_ID
HAVING COUNT(CASE WHEN DOMAIN_ID IN (2124, 2125) THEN 1 END) = 2
   AND COUNT(*) = 2

Answer 6

Thanks everyone for responding to my question.

Finally, I managed to write a query which gives me the result I wanted:

select GROUP_ID
from MY_TABLE oq
where DOMAIN_ID  in (2124, 2125)
group by GROUP_ID
having count(GROUP_ID)=2 and 
count(GROUP_ID) = (select count(iq.DOMAIN_ID) 
from MY_TABLE iq WHERE iq.GROUP_ID=oq.GROUP_ID)

Answer 7

SELECT DISTINCT GROUP_ID FROM TABLE
WHERE DOMAIN_ID IN (2124, 2125)

Something like this?