I am new to java. I had a doubt.
class ArrTest{
public static void main(String args[])
{
int i = 0;
int[] a = {3,6};
a[i] = i = 9;
System.out.println(i + " " + a[0] + " " + a[1]); // 9 9 6
}
}
This is another good example the great Java evaluation rule applies.
Java resolves the addresses from left to right. a[i]
which is the address of a[0]
, then i which is the address of i, then assign 9 to i, then assign 9 to a[0]
.
IndexOutOfBoundsException
will never be throw since a[0]
is not out of bound .
The misconception is a[9]
, which is against the left-to-right-rule
It should not.
a[i] = i = 9 (makes i equal to 9) a[0] should also be 9 since you assigned 9 to it (a[i] = i = 9), Initially a[0] was 3 and a[1] is 6 (initial value (int[] a = {3, 6};)
You should get 9 9 6.
If you do a[2] then it will give you an IndexOutOfBoundsException.
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