如何在Java中手动抛出IndexOutOfBoundsException
并选择性地打印消息?
You simply:
throw new IndexOutOfBoundsException("your message goes here");
If you need to print that message, do so from where you catch the exception. (You can reach the message with the getMessage()
method.)
Like this:
throw new IndexOutOfBoundsException("If you want a message, put it here");
This doesn't actually print the message; it just prepares it. To print the message, do something like the following:
try {
//...
throw new IndexOutOfBoundsException("If you want a message, put it here");
} catch (IndexOutOfBoundsException e) {
System.out.println(e.getMessage());
}
In the future, I'd suggest looking around for an answer before posting.
You can use the throw statement to throw an exception. The throw statement requires a single argument: a throwable object. Throwable objects are instances of any subclass of the Throwable class. Here's an example of a throw statement.
throw someThrowableObject;
Example:
public void example() {
try{
throw new IndexOutOfBoundsException();
} catch (IndexOutOfBoundsException e) {
e.printStackTrace();
}
}
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