I have a C# custom webpart on a sharepoint 2007 page. When clicking on a link in an SSRS report on another page, it sends the user to my custom webpart page with a query string like the following:
?tax4Elem=Docks%20&%20Chargers&ss=EU%20MOVEX&Phase=1&tax3Elem=Play%20IT&tax5Elem=Charger
Take note of the value for "tax4Elem", which is basically "Docks & Chargers". (The ampersand can actually come up in "tax4Elem", "tax3Elem", and "tax5Elem").
I cannot have the ampersand in that value encoded so I will have to work with this.
How do I parse this query string so that it doesn't recognize the "&" in "Docks & Chargers" as the beginning of a key/value pair?
Thanks in Advance! kate
I think you can't parse that string correctly - it has been incorrectly encoded. The ampersand in "Docks & Chargers" should have been encoded as %26
instead of &
:
?tax4Elem=Docks%20%26%20Chargers&ss=EU%20MOVEX&Phase=1&tax3Elem=Play%20IT&tax5Elem=Charger
Is it possible to change the code that generated the URL?
Obviously the request is incorrect. However, to work-around it, you can take the original URL, then find the IndexOf of &ss=
. Then, find the =
sign immediately before that. Decode (with UrlDecode ) then reencode (with UrlEncode ) the part between the =
and &ss=
(the value of tax4Elem). Then, reconstruct the query string like this:
correctQueryString = "?tax4Elem=" + reencodedTaxValue + remainderOfQueryString
and decode it normally (eg with ParseQueryString
) into a NameValueCollection
.
If you really cannot correct the URL, you can still try to parse it, but you have to make some decisions. For example:
=
after the key &\\w+
) One possible way to capture these pairs is:
MatchCollection matches = Regex.Matches(s, @"\G[?&](?<Key>\w+)=(?<Value>.*?(?=$|&\w+=))");
var values = matches.Cast<Match>()
.ToDictionary(m => m.Groups["Key"].Value,
m => HttpUtility.UrlDecode(m.Groups["Value"].Value),
StringComparer.OrdinalIgnoreCase);
You can then get the values:
string tax4 = values["tax4Elem"];
Note that if the query string is "invalid" according to our rule, the pattern may not capture all values.
或者,您可以使用HttpServerUtility.HtmlDecode
方法将值解码为'&'(与号)符号
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