Python OrderedSet with .index() method

Question

Does anyone know about a fast OrderedSet implementation for python that:

• remembers insertion order
• has an index() method (like the one lists offer)

All implementations I found are missing the .index() method.

Answer 1

You can always add it in a subclass. Here is a basic implementation for the OrderedSet you linked in a comment:

class IndexOrderedSet(OrderedSet):
    def index(self, elem):
        if key in self.map:
            return next(i for i, e in enumerate(self) if e == elem)
        else:
            raise KeyError("That element isn't in the set")

You mentioned you only need add , index , and in-order iteration. You can get this by using an OrderedDict as storage. As a bonus, you can subclass the collections.Set abstract class to get the other set operations frozenset s support:

from itertools import count, izip
from collections import OrderedDict, Set

class IndexOrderedSet(Set):
    """An OrderedFrozenSet-like object
       Allows constant time 'index'ing
       But doesn't allow you to remove elements"""
    def __init__(self, iterable = ()):
        self.num = count()
        self.dict = OrderedDict(izip(iterable, self.num))
    def add(self, elem):
        if elem not in self:
            self.dict[elem] = next(self.num)
    def index(self, elem):
        return self.dict[elem]
    def __contains__(self, elem):
        return elem in self.dict
    def __len__(self):
        return len(self.dict)
    def __iter__(self):
        return iter(self.dict)
    def __repr__(self):
        return 'IndexOrderedSet({})'.format(self.dict.keys())

You can't subclass collections.MutableSet because you can't support removing elements from the set and keep the indexes correct.