Shell script to Get a value

Question

I am trying to make a shell script, which will read number of lines (Like below) and only print "Queries per second avg: VALUE" string.

Threads: 1 Questions: 2459965658 Slow queries: 400 Opens: 103532 Flush tables: 165 Open tables: 64 Queries per second avg: 726.243

How can i realize this using shell script.?

Answer 1

sed is the traditional tool for a job like this

sed -e 's/.* Queries/Queries/' your_file

Recent versions of bash, however, support regex natively.

while read -r line ; do
    [[ $line =~ avg:\ .* ]] && echo Queries per second ${BASH_REMATCH[*]}
done < your_file

Answer 2

sed

sed -r 's/^.*(Queries.*)$/\1/'

bash

#!/bin/bash
while read -r line; do
    echo "Queries${line##*Queries}"
done

Answer 3

... | grep -o 'Queries per second avg: [0-9.]\+'