Assuming I have a class B derived from A
A defined foo() and also, B defines foo()
I have a method in another class that receives a B* (pointer to B). In that function, can I call the A::foo(), just by using the pointer to B the function received?
I think the following would do what you want:
void fun(B* b){
b->A::foo();
}
Or, of course, you can do it with type casting:
((A*)b)->foo();
or in c++ style with safety check:
dynamic_cast<A*>(b)->foo();
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