I am trying in javascript to convert an integer (which I know will be between 0 and 32), to an array of 0s and 1s. I have looked around but couldn't find something that works..
So, if I have an integer as 22 (binary 10110), I would like to access it as:
Bitarr[0] = 0
Bitarr[1] = 1
Bitarr[2] = 1
Bitarr[3] = 0
Bitarr[4] = 1
Any suggestions? Many thanks
convert to base 2:
var base2 = (yourNumber).toString(2);
access the characters (bits):
base2[0], base2[1], base2[3], etc...
var a = 22;
var b = [];
for (var i = 0; i < 5; i++)
b[i] = (a >> i) & 1;
alert(b);
Assuming 5 bits (it seemed from your question), so 0 <= a < 32
. If you like you can make the 5
larger, upto 32
(bitshifting in JavaScript works with 32 bit integer).
This should do
for(int i = 0; i < 32; ++i)
Bitarr[i] = (my_int >> i) & 1;
Building up on previous answers: you may want your array to be an array of integers, not strings, so here is a one-liner:
(1234).toString(2).split('').map(function(s) { return parseInt(s); });
Note, that shorter version, (11).toString(2).split('').map(parseInt)
will not work (chrome), for unknown to me reason it converts "0"
s to NaN
s
You might do as follows;
var n = 1071, b = Array(Math.floor(Math.log2(n))+1).fill() .map((_,i,a) => n >> a.length-1-i & 1); console.log(b);
Shortest (32 chars) version which fill last bits by zero. I assume that n
is your number, b
is base (number of output bits):
[...Array(b)].map((x,i)=>n>>i&1)
let bits = (n,b=32) => [...Array(b)].map((x,i)=>(n>>i)&1); let Bitarr = bits(22,8); console.log(Bitarr[0]); // = 0 console.log(Bitarr[1]); // = 1 console.log(Bitarr[2]); // = 1 console.log(Bitarr[3]); // = 0 console.log(Bitarr[4]); // = 1
You can convert your integer to a binary String like this. Note the base 2 parameter.
var i = 20;
var str = i.toString(2); // 10100
You can access chars in a String as if it were an array:
alert(str[0]); // 1
alert(str[1]); // 0
etc...
In addition, this code gives 32length array
function get_bits(value){
var base2_ = (value).toString(2).split("").reverse().join("");
var baseL_ = new Array(32 - base2_.length).join("0");
var base2 = base2_ + baseL_;
return base2;
}
1 => 1000000000000000000000000000000
2 => 0100000000000000000000000000000
3 => 1100000000000000000000000000000
just for the sake of refernce:
(121231241).toString(2).split('').reverse().map((x, index) => x === '1' ? 1 << index : 0).reverse().filter(x => x > 0).join(' + ');
would give you:
67108864 + 33554432 + 16777216 + 2097152 + 1048576 + 524288 + 65536 + 32768 + 16384 + 4096 + 1024 + 512 + 256 + 128 + 8 + 1
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