How do I call recursively an interface I am implementing from the implementation of this interface?
I am doing the following thing:
import io::*;
import to_str::*;
enum some_enum {
foo(~[some_enum]),
bar
}
impl to_str for some_enum {
fn to_str() -> str {
alt self {
bar { "bar" }
foo(nest) { "foo" + nest.to_str() } // this line
}
}
}
fn main() {
println(foo(~[bar,bar,bar]).to_str());
}
And it fails at compile time with
user@note ~/soft/mine/rust $ rustc example.rs && ./example
example.rs:13:32: 13:43 error: failed to find an implementation of interface core::to_str::to_str for some_enum
example.rs:13 foo(nest) { "foo" + nest.to_str() }
^~~~~~~~~~~
Of course I can do an FP-like thing:
foo(nest) { "foo" + nest.map(|x| { x.to_str() }).to_str() }
But why isn't the former case valid?
Seems like it can be solved with using impl of
instead of impl
.
impl
without of
acts like interface-less implementation, with no actual interface involved.
(confirming to http://dl.rust-lang.org/doc/tutorial.html#interface-less-implementations )
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