How do I turn a dictionary with lists as values into a list of dictionaries with single values?

Question

I have this dict:

{
  'x': [0,1,2],
  'y': ['a','b','c']
}

A dictionary where all the values are lists, of identical length.

I want to produce this:

[
  { 'x': 0, 'y': 'a' },
  { 'x': 1, 'y': 'b' },
  { 'x': 2, 'y': 'c' }
]

Is there an efficient way to do this? Hopefully using something in itertools ?

Answer 1

[dict(zip(d, vals)) for vals in zip(*d.values())]

For example:

>>> d = {'y': ['a', 'b', 'c'], 'x': [0, 1, 2]}
>>> [dict(zip(d, vals)) for vals in zip(*d.values())]
[{'y': 'a', 'x': 0}, {'y': 'b', 'x': 1}, {'y': 'c', 'x': 2}]

Answer 2

[dict(stuff) for stuff in zip(*[[(k, v) for v in vs] for k, vs in myDict.iteritems()])]

Answer 3

[{'x': v, 'y': d['y'][i]} for i, v in enumerate(d['x'])]

Answer 4

d = {
  'x': [0,1,2],
  'y': ['a','b','c']
}
values = zip(*d.values())
print [dict(zip(d.keys(), v)) for v in values]