char pointer pointing to a char array

Question

#include<stdio.h>
int main(){
 char a[3];
 char *b=NULL;
 a[0]=0;
 a[1]=1;
 a[2]=2;
 b = a;
 printf("%c",b);
 b++;
 printf("%c",b);
 b++;
 printf("%c",b);
 return 0;
}

I tried to print the values 0,1,2 by incrementing the pointer by 1. please help

Answer 1

b is a pointer in itself, you have to dereference it to get the actual values:

printf("%d", *b);
b++;
printf("%d", *b);
b++;

etc.

Answer 2

%c tells printf to interpret the char argument as a character code (most likely ASCII). Use %d instead.

Answer 3

#include<stdio.h>
int main(){
 char a[3];
 char *b=NULL;
 a[0]='0';
 a[1]='1';
 a[2]='2';
 b = a;
 printf("%c",*b);
 b++;
 printf("%c",*b);
 b++;
 printf("%c",*b);
 return 0;
}