Python: Finding the value of a character in a string

Question

Given a long string such as:

"fkjdlfjzgjkdsheiwqueqpwnvkasdakpp"

or

"0.53489082304804918409853091868095809846545421135498495431231"

How do I find the value of the nth character in that string? I could solve this if I could convert it into a list (where each digit gets it's own index) but since the numbers aren't separated by commas I don't know how to do this either.

AFAIK there is no command like string.index(10) which would return the 11th character in.

Answer 1

strings are like lists. so you can access them the same way,

>>> a = "fkjdlfjzgjkdsheiwqueqpwnvkasdakpp"
>>> print a[10]
k

Answer 2

字符串是可迭代和可索引的（因为它是序列类型 ），因此您可以使用：

"fkjdlfjzgjkdsheiwqueqpwnvkasdakpp"[10]

Answer 3

To get the corresponding character in the nth value, just use this function:

def getchar(string, n):
    return str(string)[n - 1]

Example usage:

>>> getchar('Hello World', 5)
'o'