I need to check whether the ip address resides within the range of IP.
For example 10-20.3.5.6 contains IP as
10.3.5.6 11.3.5.6 . . . 20.3.5.6
I need to know the following things:
1) 1-10.0-255.0.0-255 is the IP range I have in DB. I need to check if the IP "10.0.7.8" falls in the above specified range.
2) Consider another scenario is 10-20.10-20.10-20.10-20 I have in DB. I need to check if any one of the IP in range 10-20.10.10-30.10-50 falls in above range?
Lets try something like this...
ArrayList<String> IPlist = getIPTable(); //IPTable has entries
Pair IPranges[4] = new Pair[4]();
//Pair isa class that holds two things, like numbers;
//parse your DB entries into the IPranges
IPranges[0].low = 10; IPranges[0].hi = 20;
IPranges[1].low = 3; IPranges[1].hi = 3;
IPranges[2].low = 5; IPranges[2].hi = 5;
IPranges[3].low = 6; IPranges[3].hi = 6;
for(String IP : IPlist)
{
String octet[4]; //read the octets in the String[] octet using substring();
boolean continue = true;
for(int i = 0 ; i < 4 && continue; i++)
if(Integer.parseInt(octet[i]) >= IPtable[i].low && Integer.parseInt(octet[i]) <= IPtable[i].hi)
{
//this is good, do stuff here
}
else
continue = false; //the IP failed to pass the filter, no need to process the rest of it
//safely add the IP to the lsit of valid IPs.
validIP.add(IP);
}
private class Pair
{
public int low, hi;
public Pair(int low, int hi)
{
this.low = low; this.hi = hi;
}
} //feel free to extend this class to do the checking for you.
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.