This seems to be an easy problem but i can't figure out.
I need to convert this character < in byte(hex representation), but if i use
byte b = Convert.ToByte('<');
i get 60 (decimal representation) instead of 3c .
60 == 0x3C
.
You already have your correct answer but you're looking at it in the wrong way.
0x
is the hexadecimal prefix
3C
is 3 x 16 + 12
You could use the BitConverter.ToString
method to convert a byte array to hexadecimal string:
string hex = BitConverter.ToString(new byte[] { Convert.ToByte('<') });
or simply:
string hex = Convert.ToByte('<').ToString("x2");
get 60 (decimal representation) instead of 3c.
No, you don't get any representation. You get a byte
containing the value 60/3c in some internal representation. When you look at it , ie, when you convert it to a string (explicitly with ToString()
or implicitly), you get the decimal representation 60 .
Thus, you have to make sure that you explicitly convert the byte to string, specifying the base you want . ToString("x")
, for example will convert a number into a hexadecimal representation:
byte b = Convert.ToByte('<');
String hex = b.ToString("x");
char ch2 = 'Z';
Console.Write("{0:X} ", Convert.ToUInt32(ch2));
You want to convert the numeric value to hex using ToString("x")
:
string asHex = b.ToString("x");
However, be aware that you code to convert the "<" character to a byte will work for that particular character, but it won't work for non-ANSI characters (that won't fit in a byte).
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