I have a problem with my query:
SELECT table1.Name,
COUNT(*)
FROM table1
LEFT JOIN table2 ON table2.Name_all = table1.Name
GROUP BY table1.Name
It shows and counts a names from table1. I want to join all names from table2 which do not exist in table1.
Maybe someone knows what I am doing wrong?
Thanks in advance
From your description you seem to mean this, which is a list of name_all that does not match table1 name.
SELECT table2.Name_all
FROM table2
LEFT JOIN table1 ON table2.Name_all = table1.Name
WHERE table1.Name Is Null
If you need a count as well, you can say:
SELECT table2.Name_all, Count(table2.Name_all) AS CountOf
FROM table2
LEFT JOIN table1 ON table2.Name_all= table1.Name
WHERE table1.Name Is Null
GROUP BY table2.Name_all;
Try this
This query will fetch common names from table 1 and table 2. It will also fetch names from table 2 which are not there in table 1.
SELECT table1.Name,
table2.Name,
COUNT(*)
FROM table2
LEFT JOIN table1
ON table2.Name_all = table1.Name
GROUP BY table1.Name, table2.Name
Let me if this works.
I would do a simple in
check then
SELECT table1.Name,
FROM table1
WHERE table1.Name In (SELECT table2.Name_all FROM table2)
GROUP BY table1.Name
There are other ways, but without more information this is a simple way t
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