RTRIM from replace

Question

I have used a replace statement to I have @@@ after the name of the customer MR@BOB@REED@@@@@@@@@@@@@@@@@@@@@@@

I now want to get rid of the @ after reed .

I tried:

select RTRIM(Name2,'@')

But I get the error

The rtrim function requires 1 argument(s).

Answer 1

RTRIM removes trailing spaces.

You probably want LEFT or SUBSTRING

eg

select left('@mr@bob@reed@@@@@@@', charindex('@@','@mr@bob@reed@@@@@@@'))

Answer 2

select substring(Name2,0,charindex('@@',Name2)) from table

在上面的查询中，'Name2'是列的名称，table是包含该列的'table'的名称。