How to convert Mac string to a Byte address in C

Question

我想从命令行获取MAC地址，所以我把它作为字符串...如何将这个17字节的MAC字符串转换为“00：0d：3f：cd：02：5f”到C中的6字节MAC地址

Answer 1

On a C99-conformant implementation, this should work

unsigned char mac[6];

sscanf(macStr, "%hhx:%hhx:%hhx:%hhx:%hhx:%hhx", &mac[0], &mac[1], &mac[2], &mac[3], &mac[4], &mac[5]);

Otherwise, you'll need:

unsigned int iMac[6];
unsigned char mac[6];
int i;

sscanf(macStr, "%x:%x:%x:%x:%x:%x", &iMac[0], &iMac[1], &iMac[2], &iMac[3], &iMac[4], &iMac[5]);
for(i=0;i<6;i++)
    mac[i] = (unsigned char)iMac[i];

Answer 2

Without built-in functions and error handling simply:

unsigned char mac[6];
for( uint idx = 0; idx < sizeof(mac)/sizeof(mac[0]); ++idx )
{
    mac[idx]  = hex_digit( mac_str[     3 * idx ] ) << 4;
    mac[idx] |= hex_digit( mac_str[ 1 + 3 * idx ] );
}

Input is actually 3*6 bytes with \\0 .

unsigned char hex_digit( char ch )
{
    if(             ( '0' <= ch ) && ( ch <= '9' ) ) { ch -= '0'; }
    else
    {
        if(         ( 'a' <= ch ) && ( ch <= 'f' ) ) { ch += 10 - 'a'; }
        else
        {
            if(     ( 'A' <= ch ) && ( ch <= 'F' ) ) { ch += 10 - 'A'; }
            else                                     { ch = 16; }
        }
    }
    return ch;
}