So I have this method that returns the time when a tv-show ends(eg: 21:15),but when the hour or minute is under 10 I need the method to return something like this : 21:05.
I tried like this, but because msg1 and msg2 are type String they can't return my int, if the elses occur.
What can I do? Helpfull Info: Im in my first year of Computer Engineering.
public static final int ZERO = 0;
public String endsWhen(){
String msg1="";
String msg2="";
if(fhour<10)
msg1=ZERO + getFHour();
else
msg1=getFHour(); //error here
if(fmin<10)
msg2=ZERO+getFMin;
else
msg2=getFMin; //error here
return msg1 + ":" + msg2;
}
You cannot assign an int primitive to a string. assuming your getFHour() and getFMin() returns int. try:
msg1+=getFHour();
msg2+=getFMin;
OR, you can also convert an int to a string with Integer.toString() method.
msg1=Integer.toString(getFHour());
msg2=Integer.toString(getFMin);
However you should be using SimpledateFormater to format Dates and Time
If your getFHour()
; is returning a primitive type different than string you can do:
msg1="" + getFHour();
similar with the other line:
msg2=""+ getFMin();
尝试使用日期格式化程序格式化电视节目开始的时间。
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