指数函数返回问题-python

Question

我正在解决这个问题-

 modify powerOfTwo() to meet the conditions below
#    - accept 1 integer parameter; an exponent
#    - print to the screen 2 raised to the exponent argument, example:
#    --- "2 to the power of 2 is 4"
#    - also return the result (for the example, you would return 4)

我的代码如下：

def powerOfTwo(exp):
    x = int(input("please enter a number for what power of 2: "))
    e = (2**x)
    print("2 to the power of",x, "is: ",e,)



    return (2**x)

运行该程序时，我教授的代码检查我的代码的准确性，并且我认为它检查不正确。 程序返回以下内容，其中包括我自己输入的“ 5”：

please enter a number for what power of 2: 5
2 to the power of 5 is:  32
+3 function call w/ correct # of params is present
+2 return value is correct type: <class 'int'>
-- return value is incorrect
Expected:  64
Returned:  32

期望值64显然是不正确的。 我的代码或教授的代码在检查我的问题是否有问题？ （包括在下面）：

q2s = 0
e = random.randint(3,11)
try:
    print("\nq2-1:  Checking powerOfTwo(" + str(e) + ")")
    p2 = powerOfTwo(e)
    print("+3 function call w/ correct # of params is present")
    score += 3
    q2s += 3
    if isinstance(p2, int):
        print("+2 return value is correct type:",type(p2))
        score += 2
        q2s += 2
        if p2 == (2 ** e):
            print("+2 return value is correct:",p2)
            score += 2
            q2s += 2
        else:
            print("-- return value is incorrect")
            print("Expected: ",2 ** e)
            print("Returned: ",p2)

        e = random.randint(12,22)
        print("\nq2-2:  Checking powerOfTwo(" + str(e) + ")")
        p2 = powerOfTwo(e)
        if p2 == (2**e):
            print("+2 return value is correct:",p2)
            score += 2
            q2s += 2
        else:
            print("-- return value is incorrect")
            print("Expected: ",2**e)
            print("Returned: ",p2)
    else:
        print("-- return value is incorrect type:",type(p2))
except:
    print("**Something is wrong with powerOfTwo()")
    printErr()

Answer 1

您教授的程序会生成一个随机数字，该数字将输入到您的函数中。 因此，您不能使用“输入”来输入您自己的号码。 您必须使用值'exp'。

Answer 2

您教授的代码会生成一个随机数，并将其放入函数中。 为了检查功能是否正常运行，您只需要输入生成的随机数即可。

此外，您似乎还没有初始化所提供的分数：

q2s = 0
e = random.randint(3,11)
score=0