[英]Extracting the hour from a time column in pandas
使用to_datetime
到日期时间与dt.hour
:
df = pd.DataFrame({'TIME':['9:33:07','9:41:09']})
#should be slowier
#df['hour'] = pd.to_datetime(df['TIME']).dt.hour
df['hour'] = pd.to_datetime(df['TIME'], format='%H:%M:%S').dt.hour
print (df)
TIME hour
0 9:33:07 9
1 9:41:09 9
如果想要在列TIME
使用datetime
s,则可以分配回:
df['TIME'] = pd.to_datetime(df['TIME'], format='%H:%M:%S')
df['hour'] = df['TIME'].dt.hour
print (df)
TIME hour
0 1900-01-01 09:33:07 9
1 1900-01-01 09:41:09 9
我的建议:
df = pd.DataFrame({'TIME':['9:33:07','9:41:09']})
df['hour']= df.TIME.str.extract("(^\d+):", expand=False)
您可以使用 extract() 两次来突出“小时”列
df['hour'] = df. TIME. str. extract("(\d+:)")
df['hour'] = df. hour. str. extract("(\d+)")
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