[英]How to get a 2D NumPy array with value 1 at indices represented by values in 1D NumPy array (Python)
[英]Python: Replace 2D numpy array filled with indices by values from a 1D array
我有anxm numpy python 阵列。 该数组的值介于 0 和 10 之间,与一维 numpy 数组的索引一致(一维数组的长度 = 11,因此为 0-10)。 此一维数组存储任意值。 我现在想用一维数组中的相应值替换我的二维数组的索引值。
我怎样才能做到这一点?
干杯诺克森
numpy 很简单: result = values_1d[arr_idxs_2d]
看:
>>> import numpy as np
>>> imin, imax = 0, 9
>>> values_1d = np.random.randn(imax+1)
>>> values_1d
array([-0.80355548, 1.00645905, -1.17436992, -1.52008027, 0.73544379,
-0.72175806, -0.69933584, -0.50195895, -0.04588092, 0.86542796])
>>> arr_idxs_2d = np.random.randint(imin, imax, (4, 5))
>>> arr_idxs_2d
array([[6, 7, 4, 3, 1],
[8, 8, 3, 7, 7],
[1, 1, 5, 3, 2],
[6, 2, 3, 6, 8]])
>>> values_1d[arr_idxs_2d]
array([[-0.69933584, -0.50195895, 0.73544379, -1.52008027, 1.00645905],
[-0.04588092, -0.04588092, -1.52008027, -0.50195895, -0.50195895],
[ 1.00645905, 1.00645905, -0.72175806, -1.52008027, -1.17436992],
[-0.69933584, -1.17436992, -1.52008027, -0.69933584, -0.04588092]])
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