[英]Tensorflow - incompatible shape with conv2d after depth to space
我在实现超分辨率模型时遇到了问题
class SRNet(Model):
def __init__(self, scale=4):
super(SRNet, self).__init__()
self.scale = scale
self.conv1 = Sequential([
layers.Conv2D(filters=64, kernel_size=3,
strides=(1, 1), padding="same", data_format="channels_first"),
layers.ReLU(),
])
self.residualBlocks = Sequential(
[ResidualBlock() for _ in range(16)])
self.convUp = Sequential([
layers.Conv2DTranspose(filters=64, kernel_size=3, strides=(
2, 2), padding="same", data_format="channels_first"),
layers.ReLU(),
layers.Conv2DTranspose(filters=64, kernel_size=3, strides=(
2, 2), padding="same", data_format="channels_first"),
layers.ReLU(),
])
self.reluAfterPixleShuffle = layers.ReLU()
self.convOut = layers.Conv2D(
filters=3, kernel_size=3, strides=(1, 1), padding="same", data_format="channels_first", input_shape=(4, 1440, 2560)) # (kernel, kernel, channel, output)
def call(self, lrCur_hrPrevTran):
lrCur, hrPrevTran = lrCur_hrPrevTran
x = tf.concat([lrCur, hrPrevTran], axis=1)
x = self.conv1(x)
x = self.residualBlocks(x)
x = self.convUp(x)
# pixel shuffle
Subpixel_layer = Lambda(lambda x: tf.nn.depth_to_space(
x, self.scale, data_format="NCHW"))
x = Subpixel_layer(inputs=x)
x = self.reluAfterPixleShuffle(x)
x = self.convOut(x)
return x
错误
/usr/src/app/generator.py:164 call *
x = self.convOut(x)
ValueError: Tensor's shape (3, 3, 64, 3) is not compatible with supplied shape (3, 3, 4, 3)
阅读错误后我知道 (3, 3, 4, 3) is (kernel size, kernel size, channel, output) 意味着只有输入通道不正确
所以我打印出输入的形状
# after pixel shuffle before convOut
print(x.shape)
>>> (1, 4, 1440, 2560) (batch size, channel, height, width)
但是pixel shuffle (depth_to_space)
后x的形状pixel shuffle (depth_to_space)
是(1, 4, 1440, 2560)通道值是4,这和convOut
需要的一样
问题是为什么输入的通道会从 4 变为 64 作为错误?
我找到了解决办法
首先,我在训练时使用检查点来保存模型权重
在模型的实现和测试过程中,我改变了一些层,所以输入大小也改变了,但我的体重仍然记得上一个检查点的输入大小
所以我删除了检查点文件夹,然后一切又恢复了
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