Given the following string:
3132333435363738396162636465666768696a6b6c6d6e6f70
I converted the string to hex and now i want to file write it as hex not a string. I tried converting it to int but Integer.parseInt
converts up to 4 only and if go beyond that it would give error already.
Have you tried the BigInteger
constructor taking a string and a radix ?
BigInteger value = new BigInteger(hex, 16);
Sample code:
import java.math.BigInteger;
public class Test {
public static void main(String[] args) {
String hex = "3132333435363738396162636465666768696a6b6c6d6e6f70";
BigInteger number = new BigInteger(hex , 16);
System.out.println(number); // As decimal...
}
}
Output:
308808885829455478403317837970537433512288994552567292653424
使用BigInteger ,其中一个构造函数采用基数。
BigInteger value = new BigInteger(hexString, 16);
尝试:
new BigInteger("3132333435363738396162636465666768696a6b6c6d6e6f70", 16)
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