Python: Parse web content for lines containing a specific character and store into a file

Question

I am new to python. I have this webpage containing the contents:

<Response>
<Value type="ABC">107544</Value>
<Value type="EFG">10544</Value>
<Value type="ABC">77544</Value>

I would like to parse lines containing ABC and store only the numbers within a temporary text file. How can I do this?

Currently I have

htmlpage = urllib2.urlopen(<URL>)
result = htmlpage.read()

Answer 1

Put your result into BeautifulSoup , and you will be able to extract any data very easily without regex

UPDATED:

from bs4 import BeautifulSoup

result = '''<div class="test">
             <a href="example">Result 1</a>
            </div>

            <div class="test">
             <a href="example2">Result 2</a>
            </div>'''

soup = BeautifulSoup(result)

for div in soup.findAll('div', attrs={'class':'test'}):
    print div.find('a').text

Result 1
Result 2

Answer 2

我将建议使用BeutifulSoup来解析HTML，但是如果您坚持使用正则表达式，则可以尝试以下操作：

re.findall('(?<=type="ABC">).+?(?=<\/)', text, re.S)

Answer 3

Or lxml and xpaths

>>>from lxml import html

>>>result = html.fromstring('''<Response>
<Value type="ABC">107544</Value>
<Value type="EFG">10544</Value>
<Value type="ABC">77544</Value></Response>''')

>>>result.xpath('//value[@type="ABC"]/text()')
...['107544', '77544']