I have a string template like this:
http://server/{x}/{y}/{z}/{t}/{a}.json
And I have the values:
int x=1,y=2,z=3,t=4,a=5;
I want to know which is the efficent way to replace the {x}
to the value of x
, and so does y,z,t,z
?
String template = "http://server/%s/%s/%s/%s/%s.json";
String output = String.format(template, x, y, z, t, a);
Use MessageFormat.java
MessageFormat messageFormat = new MessageFormat("http://server/{0}/{1}/{2}/{3}/{4}.json");
Object[] args = {x,y,z,t,a};
String result = messageFormat.format(args);
Another way to do it ( C# way ;)
):
MessageFormat mFormat = new MessageFormat("http://server/{0}/{1}/{2}/{3}/{4}.json");
Object[] params = {x, y, z, t, a};
System.out.println(mFormat.format(params));
OUTPUT:
http://server/1/2/3/4/5.json
http://server/{x}/{y}/{z}/{t}/{a}.json
如果您可以将其更改为http://server/{0}/{1}/{2}/{3}/{4}.json
,则可以使用MessageFormat
:
String s = MessageFormat.format("http://server/{0}/{1}/{2}/{3}/{4}.json", x, y, z, t, a);
To replace the placeholders exact how you use them in example, you can use StrinUtils.replaceEach
org.apache.commons.lang.StringUtils.replaceEach(
"http://server/{x}/{y}/{z}/{t}/{a}.json",
new String[]{"{x}","{y}","{z}","{t}","{a}"},
new String[]{"1","2","3","4","5"});
However, MessageFormat
will be more efficient, but requiring to replace x with 0, y with 1 etc.
If you change your format to
"http://server/${x}/${y}/${z}/${t}/${a}.json",
you can consider using Velocity , which has parser specialized on finding ${ and } occurences.
The most efficient way would be to write own parser searching for next { occurence, than }, than replacing the placeholder.
This Could be probable answer.
String url= "http://server/{x}/{y}/{z}/{t}/{a}.json";
int x=1,y=2,z=3,t=4,a=5;
url = url.replaceAll("\\{x\\}", String.valueOf(x));
url = url.replaceAll("\\{y\\}", String.valueOf(y));
url = url.replaceAll("\\{z\\}", String.valueOf(z));
url = url.replaceAll("\\{t\\}", String.valueOf(t));
url = url.replaceAll("\\{a\\}", String.valueOf(a));
System.out.println("url after : "+ url);
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