Is there a way to compare if a primitive type and an array are less than zero?

Question

In java, you cannot use .compareTo() to compare primitive types (like an int) with something else.

Is there a way to compare if two integers are less than zero? I am trying to compare an integer to a spot in an array.

Thanks!

SOLVED: Sorry everyone, had a massive brain cramp for a second. I forgot that a.compareTo(b) returns -1, 0, or 1 based on if the first value is less than(returns -1), equal to(returns 0),or greater than (returns 1). My code said int.compareTo(array)<0 when really all it needed to say was int

Answer 1

use like this

  if(firstinteger<0 && secondinteger<0){

   }

Answer 2

== if compared against primitives will either perform numerical or boolean equality . That said, for what you want, it should be as trivial as doing this:

if(firstValue < 0 && secondValue < 0) {
    // operate
}

Remember: You only use .compareTo for references that implement Comparable (such as Integer , Long , etc). You use == for all other numerical primitives. ¹

^{1: But watch out for floating-point values. Those may not always equal each other.}