Array comparison for integer

Question

Here I am comparing two array element , If array element are equal SETPASSWORD=1; else SETPASSWORD=0; But Here It is always printing password set status 1 even array are not equal

#include <stdio.h>
#define ARY_SIZE 4
int password_set;
int main (void)
{
  //Local Declarations
  int numbersA[ARY_SIZE];
  int numbersB[ARY_SIZE];
  int i;
  int j;

  //Statements
  printf("Please Enter 10 Integers For Array A\n");
  for (int i = 0; i < ARY_SIZE; i++)
    scanf("%d", &numbersA[i]);

  printf("\nPlease Enter 10 Integers For Array B\n");
  for (int j = 0; j < ARY_SIZE; j++)
    scanf("%d", &numbersB[j]);

  for (int i = 0; i < ARY_SIZE; i++)
  {
    for (int j = 0; j < ARY_SIZE; j++)
    {
      if (numbersA[i] == numbersB[j])
        password_set=1;
      else
        password_set=0;
    }
  }
  printf(" password setstaus =%d",password_set);
  return 0;
}

Answer 1

Your logic is wrong. You must exit the loop as soon as one pair of numbers is non equal.

And you also need only one loop :

password_set = 1 ;

for (int j = 0; j < ARY_SIZE; j++)
{
  if (numbersA[j] != numbersB[j])
  {
    password_set = 0;
    break ;
  }
}

Answer 2

Your compare each value of the array in your for (if (numbersA[i] == numbersB[j])

It resets the value of password_set at each iterations. It means that the result printed will be the last index of your array.

And btw you need only one loop

Answer 3

Actually, you comparison is wrong. Because you want to test two arrays is equal or not, you just test each number of these two arrays.

like this:

    password_set = 1;

    for (int i = 0; i < ARY_SIZE; i++) {
        if (numbersA[i] != numbersB[i]) {
            password_set=0;
            break;
        }
    }