I have a string:
__cfduid=d2eec71493b48565be764ad44a52a7b191399561601015; expires=Mon, 23-Dec-2019 23:50:00 GMT; path=/; domain=.planetminecraft.com; HttpOnly
I want to use regex and get something like this:
[0] = __cfduid=d2eec71493b48565be764ad44a52a7b191399561601015
[1] = expires=Mon, 23-Dec-2019 23:50:00 GMT
[2] = path=/
[3] = domain=.planetminecraft.com
[4] = HttpOnly
I tried this regex:
[\A|;](.*?)[\Z|;]
I don't understand why \\A
. works but [\\A]
not, how can I create ( \\A
or ;
)?
In final form of this regex I want to get from string this:
[0] = {
[0] = __cfduid
[1] = d2eec71493b48565be764ad44a52a7b191399561601015
}
[1] = {
[0] = expires
[1] = Mon, 23-Dec-2019 23:50:00 GMT
}
[2] = {
[0] = path
[1] = /
}
[3] = {
[0] = domain
[1] = .planetminecraft.com
}
[4] = {
[0] = HttpOnly
}
Square brackets create a character class ; you need parentheses for grouping, preferably non- capturing groups . And you need to use a positive lookahead assertion instead of the second group since each semicolon can only match once:
(?:\A|;)(.*?)(?=\Z|;)
That still doesn't get you your parameter/value pairs, so you might want to be more specific:
(?:\A|;\s*)([^=]*)(?:=([^;]*))?(?=\Z|;)
( [^=]*
matches any number of characters except =
.)
See it live on regex101.com .
You can try matching on this regex:
\s*([^=;]+)(?:=([^=;]+))?
Description:
\s* # Match any spaces
([^=;]+) # Match any non = or ; characters
(?:
= # Match an = sign
([^=;]+) # Match any non = or ; characters.
)? # Make this group optional
In code:
string text = "__cfduid=d2eec71493b48565be764ad44a52a7b191399561601015; expires=Mon, 23-Dec-2019 23:50:00 GMT; path=/; domain=.planetminecraft.com; HttpOnly";
var regex = new Regex(@"\s*([^=;]+)(?:=([^=;]+))?");
var matches = regex.Matches(text);
foreach (Match match in matches)
{
Console.WriteLine(match.Groups[1].Value + "\n" + match.Groups[2].Value + "\n");
}
\\A
works but [\\A]
does not because when you put \\A
in a character class, it loses its meaning like most regex metacharacters. For instance, +
and *
also lose their meaning. In [\\A]
, the regex is actually trying to match \\A
and since it doesn't have a particular meaning in a character class, it means a literal A
.
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