How to print right side result continously in python?

Question

I have my code:

for i in range(0,5):
    print "result is:"+str(i),

This prints:

result is:0 result is:1 result is:2 result is:3 result is:4

I want to print like this:

result is:0,1,2,3,4

How to do it in python?

Answer 1

print('Result is: {}'.format(', '.join(map(str, range(5)))))

prints

Result is: 0, 1, 2, 3, 4

Valid for Python 2 and Python 3.

Explanation:

range(5) is the same as range(0, 5) . map(str, x) , given an iterable x, returns a new iterable having all the items in x stringified ( e -> str(e) ). ', '.join(iterable) joins a given iterable (list, generator, etc) whose elements are strings, into a string 1 string using the given separator. Finally str.format() replaces the {} placeholders with its arguments in order.

Answer 2

Since you want to print all the elements of the list, you can convert all the numbers to string and join all of them together with , , like this

print "result is:" + ",".join(str(number) for number in range(0, 5))

Since the range 's default start parameter is 0, you can call it like this

print "result is:" + ",".join(str(number) for number in range(5))

Also, you can use templated strings like this

print "result is: {}".format(",".join(str(number) for number in range(5)))

You can apply the str function to all the elements of the number list, with map function, like this

print "result is: {}".format(",".join(map(str, range(5)))

Answer 3

x = 'result is: ';
for i in range(0,5):
    x += str(i) + ',';
print(x[:-1];

will do what you want. In a highly legible form although not the best speed possible.

Answer 4

Another version of the same thing:

for i in range(0,5):
    if i == 0:
        print "result is %d" % i,
else:
    print ",%d" % i,

Answer 5

In Python3 you can use the end kwarg of the print function. This is not possible in Python2.

print("The result is: ", end="")
for i in range(5):
    print(str(i)+", ", end="")