how to loop through arrays and print each index side by side in python?
Question
Simply put, I want to print three arrays with strings in between each. For example,
print(item + string + description + string + price).
I have the 3 arrays but this code only prints the first six lines.
res = "\n".join("{} {} {} {} {} {} {}".format(html, x, html, z, html, w, html) for x, y, z, v, w in zip(itemList, html, priceList, html, descripList))
print(res)
I'm surprised something simple like this is not already answered on Stack Overflow, everything I find is not practical but rather theoretical.
Here is my full code:
itemList=[]
for tag in soup.find_all('a', class_=['menuItem-name']):
if tag not in itemList:
itemList.append(tag.text)
descripList=[]
for t in soup.find_all('span', class_=['u-text-secondary']):
if t not in descripList:
descripList.append(t.text)
priceList=[]
for g in soup.find_all('p', class_=['menuItem-displayPrice']):
if g not in priceList:
priceList.append(g.text)
html="<html>"
res = "\n".join("{} {} {} {} {} {} {}".format(html, x, html, z, html, w, html) for x, y, z, v, w in zip(itemList, html, priceList, html, descripList))
print(res)
2 answers
solution1
3 ACCPTED 2020-10-27 16:39:15
putting "<html>" into zip will iterate through all 6 chars in that string and then finish. Try:
res = "\n".join("{} {} {} {} {} {} {}".format(html, x, html, z, html, w, html) for x, z, w in zip(itemList, priceList, descripList))
solution2
1 2020-10-27 16:38:59
zip is truncating its work at the shortest iterable passed to it; one of its arguments only has a length of 6
>> [x for x in zip(range(3), range(4), range(5))]
[(0, 0, 0), (1, 1, 1), (2, 2, 2)]
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