Python Regular expression to extract a substring

Question

I have a string

" request.addParameter('page','/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag','N','',true,false); " .

I want to extract the part

" '/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag' "

out of this string. I tried several combinations of regex (using re module in python) but can't find the exact desired pattern that gives me the substring out of the main string.

Answer 1

'([^']+)'

You can try this.

Do print re.findall(r"'([^']+)'",x)[1] .

Here x is your string.Basically it is extracting the second group.

See demo.

http://regex101.com/r/yG7zB9/2

Answer 2

Use the regex

'\/[^']+'

The code can be written as

x="  request.addParameter('page','/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag','N','',true,false); ".
re.findall(r"'\/[^']+'", x)"
["'/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag'"]

see how the regex works http://regex101.com/r/pK9mI8/1

you can also use search function to search and find the substring matching the pattern as

 re.search(r"'\/[^']+'", x).group()
"'/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag'"

Answer 3

Seems like you want something like this,

>>> import re
>>> s = "  request.addParameter('page','/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag','N','',true,false); "
>>> re.search(r"'(/[^']*)'", s).group(1)
'/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag'

Answer 4

You are not forced to use regex you can use split() :

>>> s.split(',')[1]
"'/TMRMKUOHY/RPM/Store/srrreVkew.jsp?resODFlag'"