In the programme the user must enter a password, if he gets it wrong the programme will prompt him 2 more times and if he does not get right those 2 times the programme will expire. How do I go about doing this. This is my programme so far...
password=input("Enter password:")
while password != 'cat':
print ("password is wrong, try it again")
password= input ("Enter your password:")
print ("Password correct be happy")
for trial in range(3):
print ("Attempt no.",trial, end=" ")
passw = input('. Enter password > ')
if passw == 'cat' : break
else:
passw = 'cat'
Yes, also the humble for
loop has an else
clause: "Loop statements may have an else clause; it is executed when the loop terminates through exhaustion of the list (with for) or when the condition becomes false (with while), but not when the loop is terminated by a break statement." .
try this:
import sys
max_tries = 3; current_tries = 0
password=input("Enter password:")
while password != 'cat':
if current_tries > max_tries:
print "too many tries"
sys.exit(0)
print ("password is wrong, try it again")
password= input ("Enter your password:")
current_tries +=1
print ("Password correct be happy")
max_tries = 3
password = None
for i in range(max_tries):
password = input("Enter Password:")
if password == "cat": break
if password != "cat":
print ("ERROR TOO MANY TRIES!")
else:
print ("You Win!")
is a simple way to do it ...
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